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def solution(n):
d=[0]*(n+2)
d[1]=1
d[2]=2
for i in range(3, n+1):
d[i]= (d[i-1]+d[i-2])%1234567
return d[n]
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def solution(n):
d=[0]*(n+2)
d[1]=1
d[2]=2
for i in range(3, n+1):
d[i]= (d[i-1]+d[i-2])%1234567
return d[n]